widget.isVisible API doesn't work properly

XMLWordPrintable

    • Type: Bug
    • Resolution: Fixed
    • Priority: Normal
    • 6.5.3
    • Affects Version/s: 6.5.2
    • Component/s: Components
    • None
    • None

      If use pure client side

      1. create a widget (without append to a parent), without render widget's DOM element on HTML document
      2. invoke widget.isVisible(true), according to the API, when pass "true" argument, will check whether DOM element is visible or not

      result: return "true"

      BTW since the widget is not render yet, there's no DOM element, should return false

      Also refer to append file

            Assignee:
            vincentjian
            Reporter:
            samchuang
            Votes:
            0 Vote for this issue
            Watchers:
            0 Start watching this issue

              Created:
              Updated:
              Resolved: