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Type:
Bug
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Resolution: Fixed
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Priority:
Normal
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Affects Version/s: 6.5.2
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Component/s: Components
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None
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None
If use pure client side
1. create a widget (without append to a parent), without render widget's DOM element on HTML document
2. invoke widget.isVisible(true), according to the API, when pass "true" argument, will check whether DOM element is visible or not
result: return "true"
BTW since the widget is not render yet, there's no DOM element, should return false
Also refer to append file