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  1. ZK
  2. ZK-1692

widget.isVisible API doesn't work properly

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    • Icon: Bug Bug
    • Resolution: Fixed
    • Icon: Normal Normal
    • 6.5.3
    • 6.5.2
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      If use pure client side

      1. create a widget (without append to a parent), without render widget's DOM element on HTML document
      2. invoke widget.isVisible(true), according to the API, when pass "true" argument, will check whether DOM element is visible or not

      result: return "true"

      BTW since the widget is not render yet, there's no DOM element, should return false

      Also refer to append file

            vincentjian vincentjian
            samchuang samchuang
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